How to swap two numbers without using temporary variable in C++ Language?

Introduction: Swapping the value of two numbers in C++ is not a difficult task. But how many of us actually know that there are multiple ways to swap the value of two numbers/variables in C++ language. There are a number of ways to swap the value of two numbers in C++.  In this article I am going to use Addition (+) and Subtraction (–) arithmetic operators to help in swapping. In my previous article i  explained "What is C++ Language ? Calculate sum of two numbers in C++ Language" and
“How to swap two numbers in C++ Language” i explained how to swap two numbers using temporary variable in C++. .

Implementation: Let's create a program to swap the value of 2 numbers.

#include<iostream.h>

#include<conio.h>

void main()

{

 clrscr();

 int a,b;

 cout<<"Enter first number= ";

 cin>>a;

 cout<<"Enter second number= ";

 cin>>b;

 cout<<"\nValue of first number before swapping= "<<a;

 cout<<"\nValue of second number before swapping= "<<b;

 a=a+b;

 b=a-b;

 a=a-b;

 cout<<"\nValue of first number after swapping= "<<a;

 cout<<"\nValue of second number after swapping= "<<b;

 getch();

 }

Run the program using ctrl+F9

Output:

Enter first number= 20

Enter second number= 50

Value of first number before swapping= 20

Value of second number before swapping= 50

Value of first number after swapping= 50

Value of second number after swapping= 20

Now over to you:

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