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Another way to swap two numbers without using temporary variable in C++ Language?

Introduction: How to swap the value of two numbers in C++ is very basic task. There are a number of ways to swap the value of two numbers in C++.  In this article I am going to use Multiplication (*) and Division (/) arithmetic operators to help in swapping. In my previous article “How to swap two numbers in C++ Language ” i explained how to swap two numbers using temporary variable and there is a also another article “How to swap two numbers without using temporary variable in C++Language” that explains another way to swap two numbers without using temporary variable in C++ .

Implementation: Let's create a program to swap the value of two numbers.

#include<iostream.h>
#include<conio.h>
void main()
{
 clrscr();
 int a,b;
 cout<<"Enter first number= ";
 cin>>a;
 cout<<"Enter second number= ";
 cin>>b;
 cout<<"\nValue of first number before swapping= "<<a;
 cout<<"\nValue of second number before swapping= "<<b;
 a=a*b;
 b=a/b;
 a=a/b;
 cout<<"\nValue of first number after swapping= "<<a;
 cout<<"\nValue of second number after swapping= "<<b;
 getch();
 }

Run the program using ctrl+F9

Output:
Enter first number= 20
Enter second number= 50

Value of first number before swapping= 20
Value of second number before swapping= 50
Value of first number after swapping= 50
Value of second number after swapping= 20

Now over to you:
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